Worked example
A 10 kg dog is estimated 8% dehydrated, has 120 mL/day of ongoing losses, uses 60 mL/kg/day maintenance, and the plan is to replace over 24 hours.
Maintenance = 10 kg x 60 mL/kg/day = 600 mL/day
Deficit = 10 kg x 8 x 10 = 800 mL
Losses over 24 hr = 120 mL
Total = 600 + 800 + 120 = 1,520 mL, or 63.3 mL/hr
The teaching point is to keep maintenance, deficit, and losses mentally separate even when the final rate is shown as one number.