Worked example
A 10 kg dog has a sodium of 165 mEq/L, target 150 mEq/L, and total body water factor 0.6.
Total body water = 10 kg x 0.6 = 6 L
Free water deficit = 6 x ((165 / 150) - 1) = 0.6 L
The planning estimate is 0.6 L of free water deficit, which still needs a separate decision about pacing, fluids, and monitoring.